In this assignment, you will design the microphone pre-amplifier highlighted with red in the block diagram, which is a differential amplifier as shown in the schematics below.

Differential AmplifierDesign

In this assignment, you will design the microphone pre-amplifier highlighted with red in the block diagram,

which is a differential amplifier as shown in the schematics below.

Your design should satisfy the required differential gain, input impedance, single-ended common-mode

gain, and the power dissipation specifications provided in Section A below. Then in Sections B and C, you

will simulate your circuit on LTSpice to compare the simulation results with hand calculations.

 

 

  1. Hand design: Design the bipolar differential amplifier and the current source and bias network

(𝑅1, 𝑄3, π‘Žπ‘›π‘‘ 𝑄4) above such that:

(i) Differential gain: 𝐴𝑑 β‰₯ 200 𝑉

𝑉,

(ii) Input differential resistance: 𝑅𝑖𝑑 β‰₯ 50 π‘˜Ξ©,

(iii) π΄π‘π‘š < 0.1 where π΄π‘π‘š is the single-ended common-mode gain (the gain to a common-mode input

signal when the output is measured not differentially but from one of the outputs with respect to ground).

(iv) To keep the battery discharge lifetime long, the power consumption of the differential amplifier,

𝑃𝑇𝑂𝑇𝐴𝐿, must be less than 2 milliwatts.

Design the circuit with BJTs having 𝛽 = 200, 𝑉𝐴 = 100 𝑉, π‘Žπ‘›π‘‘ 𝑉𝐡𝐸 = ~0.7 𝑉 𝑖𝑛 πΉπ‘œπ‘Ÿπ‘€π‘Žπ‘Ÿπ‘‘ 𝐴𝑐𝑑𝑖𝑣𝑒. Use

+𝑉𝐷𝐷 = 9 𝑉 and βˆ’π‘‰π‘†π‘† = βˆ’9 𝑉. Clearly show your steps.

Design Suggestion for Part A.

  1. Derive the expression for 𝑅𝑖𝑑 (ignore π‘Ÿπ‘œ of Q1 and Q2.). Replace the small signal parameter(s) with

β€œdc currents”, β€œresistors”, β€œπ‘‰π‘‘β„Ž”, β€œπ›½β€, β€œπ‘‰π΄”, etc. and simplify the expressions to the extent possible

(e.g., manipulate the expressions and then replace 𝑉𝐴 = 100 𝑉, 𝛽 = 200, etc.). The 𝑅𝑖𝑑 design

specification will let you find an upper limit for Q1 (and Q2) dc collector current, 𝐼𝐢1(= 𝐼𝐢2).

  1. The total power dissipation is 𝑃𝑇𝑂𝑇𝐴𝐿 = 𝑃𝑉𝐷𝐷 + 𝑃𝑉𝑆𝑆 = 9𝑉 βˆ— (𝐼𝑉𝐷𝐷 + 𝐼𝑉𝑆𝑆). Here, 𝐼𝑉𝐷𝐷 is the sum

of all dc currents leaving the +𝑉𝐷𝐷 and 𝐼𝑉𝑆𝑆 is the sum of all dc currents entering the βˆ’π‘‰π‘†π‘†. In

𝑃𝑇𝑂𝑇𝐴𝐿 write 𝐼𝑉𝐷𝐷 and 𝐼𝑉𝑆𝑆 in terms of Q1 (or Q2) collector currents (ignore the current on the

reference current generation branch formed by 𝑅1 and 𝑄4). The 𝑃𝑇𝑂𝑇𝐴𝐿 design specification will

let you find another upper limit for 𝐼𝐢1(= 𝐼𝐢2).

  1. Derive the expressions for 𝐴𝑑 and π΄π‘π‘š. (When deriving 𝐴𝑑, include π‘Ÿπ‘œ of Q1 or Q2. When deriving

π΄π‘π‘š ignore π‘Ÿπ‘œ of Q1 and Q2 but include π‘Ÿπ‘œ of Q3.). Replace the small signal parameter(s) with β€œdc

currents”, β€œresistors”, β€œπ‘‰π‘‘β„Ž”, β€œπ›½β€, β€œπ‘‰π΄”, etc. and simplify the expressions to the extent possible

(e.g., manipulate the expressions and then replace 𝑉𝐴 = 100 𝑉, 𝛽 = 200, etc.). The 𝐴𝑑 and π΄π‘π‘š

design specifications will let you respectively find lower and upper limits for the product 𝑅𝐢 βˆ— 𝐼𝐢1.

  1. Consider the forward-active region requirement of Q1 (or Q2). For 𝑉𝐢𝑀 = 0 𝑉, find another upper

limit for the product 𝑅𝐢 βˆ— 𝐼𝐢1.

  1. Consider the upper limits for 𝐼𝐢1 to pick an 𝐼𝐢1. Find 𝑅1 based on the value you pick for 𝐼𝐢1. Then

use the upper and lower limits for 𝑅𝐢 βˆ— 𝐼𝐢1 to pick 𝑅𝐢.

In your simulations, use the BJT model 2N2222 of NXP, which has a SPICE model as below with 𝑉𝐴 and 𝛽

highlighted:

 

 

  1. DC Analysis: In LTSpice do a DC operating point simulation (.op) with both inputs connected to ground

(i.e., 𝑉𝐢𝑀 = 0 𝑉). Find the simulated DC values for 𝐼𝑅1, 𝐼𝐢3, 𝐼𝐢4, 𝐼𝐢1, 𝐼𝐢2, 𝑉𝐡3, 𝑉𝐸1,2, 𝑉𝑂1, 𝑉𝑂2. Compare them

with your hand calculations. Additionally, comment on the matching between 𝐼𝑅1 π‘Žπ‘›π‘‘ 𝐼𝐢3 and comment

on the theoretical vs. simulated match between 𝐼𝑅1 π‘Žπ‘›π‘‘ 𝐼𝐢3.

  1. Transient Analysis: In LTSpice do a transient simulation (.tran) for 100 ms.

For differential small-signal input simulations:

Apply 𝑣𝑖𝑑 = 1 π‘šπ‘‰π‘ π‘ π‘–π‘›π‘’π‘ π‘œπ‘–π‘‘π‘Žπ‘™ π‘ π‘–π‘”π‘›π‘Žπ‘™ π‘Žπ‘‘ 100 𝐻𝑧. [i.e., 𝑣𝑖𝑑1 = + 𝑣𝑖𝑑

2 = 0.5 π‘šπ‘‰ sin (2 βˆ— πœ‹ βˆ— 100𝐻𝑧 βˆ— 𝑑)

and 𝑣𝑖𝑑2 = βˆ’ 𝑣𝑖𝑑

2 = 0.5 π‘šπ‘‰ sin ((2 βˆ— πœ‹ βˆ— 100𝐻𝑧 βˆ— 𝑑) + πœ‹) with DC offset = 0V. ]

For common-mode small-signal input simulations:

Apply π‘£π‘π‘š = 1 π‘šπ‘‰π‘ π‘ π‘–π‘›π‘’π‘ π‘œπ‘–π‘‘π‘Žπ‘™ π‘ π‘–π‘”π‘›π‘Žπ‘™ π‘Žπ‘‘ 100 𝐻𝑧. [i.e., π‘£π‘–π‘π‘š1 = π‘£π‘–π‘π‘š2 = π‘£π‘π‘š = 1 π‘šπ‘‰ sin (2 βˆ— πœ‹ βˆ—

100𝐻𝑧 βˆ— 𝑑) with DC offset = 0V.]

  1. For the differential small-signal input, what is the expected emitter voltage of Q1 and Q2,

𝑣𝑒1(= 𝑣𝑒2)? Plot the simulated waveform. What is the simulated value of 𝑣𝑒1(= 𝑣𝑒2)?

  1. Plot 𝑣𝑖𝑑, π‘£π‘œπ‘‘(π‘£π‘œπ‘‘ = π‘£π‘œ2 βˆ’ π‘£π‘œ1), π‘Žπ‘›π‘‘ 𝑖𝑖𝑑. Note that 𝑖𝑖𝑑 is the base current of Q1 (𝑖𝑖𝑑 = 𝑖𝑏1).

Calculate the simulated 𝐴𝑑 = π‘£π‘œπ‘‘/𝑣𝑖𝑑 and 𝑅𝑖𝑑 = 𝑣𝑖𝑑/𝑖𝑖𝑑. Compare the values with your

design targets.

  1. If the simulation results do not match the design constraints, tune your circuit to achieve the

goals.

  1. For the common-mode small-signal input, plot π‘£π‘π‘š and π‘£π‘œπ‘π‘š. (π‘£π‘œπ‘π‘š = π‘£π‘œπ‘π‘š2 =

π‘£π‘œπ‘π‘š1 π‘€β„Žπ‘’π‘› π‘‘β„Žπ‘’ 𝑖𝑛𝑝𝑒𝑑 𝑖𝑠 π‘Ž π‘π‘œπ‘šπ‘šπ‘œπ‘› βˆ’ π‘šπ‘œπ‘‘π‘’ π‘ π‘–π‘”π‘›π‘Žπ‘™)