Compute the maximum number of Type A actuators that can be made and stay within the time constraints of all workstations. What is the profit? For completeness, do the same calculations if you only produce Type B actuators?

1. Solve the following linear model graphically to find optimal values of the decision variables
π‘₯1and π‘₯2 that maximize the objective function, z. (FYI, we designate the optimal objective
function value as z* and the values of the decision variable that produce this π‘₯1
βˆ—
and π‘₯2
βˆ—
.)
Max 𝑧 = 2π‘₯1 + π‘₯2
s.t. π‘₯2 ≀ 10
3π‘₯1 + 4π‘₯2 ≀ 60
2π‘₯1 + π‘₯2 ≀ 30
π‘₯1 ≀ 14
π‘₯1 β‰₯ 0, π‘₯2 β‰₯ 0
2. Consider the following linear model where 𝑐1 has not yet been defined.
Max 𝑧 = 𝑐1π‘₯1 + π‘₯2
s.t. π‘₯1 + π‘₯2 ≀ 6
π‘₯1 + 2.5π‘₯2 ≀ 10
π‘₯1 β‰₯ 0, π‘₯2 β‰₯ 0
Use the graphical approach that we covered to find the optimal solution, x*=(π‘₯1
βˆ—
, π‘₯2
βˆ—
) for all values
of βˆ’βˆž ≀ 𝑐1 ≀ ∞.
Hint: First draw the feasible region and notice that there are only a few corner points that can be
the optimal solution. Also remember that if the objective function line reaches a maximum and
it includes two adjacent corner points, both of these points and all of the points that create the
line that connects them are optimal. There is literally an infinite number of optimal solutions …
but only one optimal objective function value because if you plug in the values of x1 and x2 you
get the same (max) value.
Now, 𝑐1 controls that slope of the objective function line and this is the critical concept. Go to
any of the corner points and some values of c1 that make that point the optimal solution. Then
ask yourself how much can the slope increase (or decrease) that will move the optimal solution
to an adjacent corner point. That range is the answer to this question.
3. A fabrication shop makes two types of valve actuators for explosive environments – call them
A and B. This actuator requires special manufacturing processes so there is one production line
dedicated exclusive to producing them. The line consists of three workstations (w/s 1, w/s 2, and
w/s 3). Demand for actuators is robust so you can assume that all are sold as soon as they are
produced. Your task is to find the right mix of actuators to produce that maximizes profit.
Production of both types of actuators uses the same linear routing: raw materials goes to w/s 1;
output of w/s 1 goes to w/s 2; output of w/s 2 goes to w/s 3. At this point the actuators are
completed and go to pack and ships. Details of the processing times are provided in the
technology table below along with the total number of hours available at each w/s and the profit
realized for selling an actuator of each type. w/s 1
(hours)
w/s 2
(hours)
w/s 3
(hours)
Profit/actuator
($)
Type A 16.5 10.0 1.6 875
Type B 8.5 13.0 1.7 800
Time available (hours) 150 137 22.5
One member of the management team doesn’t trust math models and loudly proclaim the
obvious answer is to produce the maximum number of Type A actuators and discontinue Type B
because A’s are the most profitable. He argues that even if the model says something different,
it is because the analyst is β€œplaying with the numbers to make it say what they want it to say.”
You need to address this because this person is somewhat influential in addition to being loud.
a) Compute the maximum number of Type A actuators that can be made and stay within the time
constraints of all workstations. What is the profit? For completeness, do the same calculations if
you only produce Type B actuators?
b) Now, use linear programming to find the solution that maximizes profit. For now, assume
that we can produce fractions of actuators so the number to produce can be a continuous variable
and we can use the methodology covered in the lessons. To find the number of Type A and Type
B actuators that will maximize profit, perform the following step:
β€’ Write the model in equation form. Let xA and xB be the number of actuators of type A
and B to produce, respectively.
Hint: You model will look something like problems 1 and 2. If z is the total profit the it
will be equal to the profit gained from producing xA units of Type A plus the profit
gained from producing xB units of Type B. There will be constraints for the each of the
w/s’s that ensure the time used to produce xA and xB is less than the total time available.
β€’ Solve the model graphically for x* = (
*
A
x ,
*
B
x
)
β€’ Compute the optimal profit (z*) that corresponds to x*.
β€’ Compare this answer with your answers in part a) and note what you find. Which
solution has the higher profit? What differences do you see in how the solutions utilize
the w/s’s?
c) Sometimes rounding up and down from the optimal solution of the β€œrelaxed” problem (i.e.,
assuming variables that are really integers are continuous) doesn’t give you the optimal solution
to the real/integer problem … and sometimes it does. Conceptually, the reason is because you
might be able utilize the constrained resources better a bit further from the optimal solution to the
relaxed problem than just rounding up and down. In practical problems, it frequently doesn’t
matter much but it is an important point for you to understand because when profit margins are
close, a little improvement can mean a lot. Anyway, you are now being asked to find the optimal
integer solution using brute force enumeration using a spreadsheet that has six columns:
Type A Type B w/s 1 w/s 2 w/s/3 Profit

Use the first two columns to identify all possible solutions. Vary the number of Type A
actuators from 3 to 10 and, for each number of Type A actuators, vary the number of Type Bactuators from 3 to 11. That is, there will be 72 rows with the first two columns (Type A, Type
B) = (3,3), (3,4), (3,5), … (10,11).
Use columns 3 through 5 to determine if the solution is feasible. To do this, compute the time
required for the workstation to produce the actuations in the first two columns requires. Then
check to see each is less than the maximum available. (You can use an IF statement if you know
how they work or do the checking by hand.) You should be able to do this for the first
row/solution, then copy and paste for the rest. Identify any rows that are infeasible by
highlighting the cells in those rows.
For each of the feasible solutions, compute the profit and identify the one that is the maximum.
Is this solution the same as rounding the one is part b up and/or down? Any thoughts on this